chentongxin this.btnLogin.on(Laya.Event.CLICK, null, this.OnLoginClick); LoginView.prototype.OnLoginClick= function() { this.dlg.setContent("暂时无法登录"); };解决方法式在第一行代码第二个参数一定要传this(被某老师坑惨)如这样: this.btnLogin.on(Laya.Event.CLICK, this, this.OnLoginClick);